The sum of 6 consecutive odd integers exceeds twice the biggest integer integer by 38. Find sum of the six numbers?
Created: 6 years ago |
Updated: 3 years ago
best des
let, 6 consecutive odd integer are: 2n - 5, 2n - 3, 2n - 1, 2n + 1, 2n + 3, 2n + 5.
so, (2n - 5) + (2n - 3) + (2n - 1) + (2n + 1) + (2n + 3) + (2n + 5) = 2.(2n + 5) + 38
বা, 12n = 4n + 10 + 38
বা, 8n = 48
so, n = 6
sum of six numbers = 12 * 6 = 72
Md Azizur Rahman
Founder of Satt
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